Base | Representation |
---|---|
bin | 11000011010001001… |
… | …10001000111100001 |
3 | 1020211020222011001201 |
4 | 30031010301013201 |
5 | 203314142133312 |
6 | 10004153401201 |
7 | 642510222256 |
oct | 141504610741 |
9 | 36736864051 |
10 | 13104255457 |
11 | 5615013097 |
12 | 2658709201 |
13 | 130ab75417 |
14 | 8c454742d |
15 | 51a697557 |
hex | 30d1311e1 |
13104255457 has 2 divisors, whose sum is σ = 13104255458. Its totient is φ = 13104255456.
The previous prime is 13104255421. The next prime is 13104255473. The reversal of 13104255457 is 75455240131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7727113216 + 5377142241 = 87904^2 + 73329^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13104255457 is a prime.
It is a super-2 number, since 2×131042554572 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13104225457) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552127728 + 6552127729.
It is an arithmetic number, because the mean of its divisors is an integer number (6552127729).
Almost surely, 213104255457 is an apocalyptic number.
It is an amenable number.
13104255457 is a deficient number, since it is larger than the sum of its proper divisors (1).
13104255457 is an equidigital number, since it uses as much as digits as its factorization.
13104255457 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 84000, while the sum is 37.
Adding to 13104255457 its reverse (75455240131), we get a palindrome (88559495588).
The spelling of 13104255457 in words is "thirteen billion, one hundred four million, two hundred fifty-five thousand, four hundred fifty-seven".
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