Base | Representation |
---|---|
bin | 11000011010001001… |
… | …11100101111000001 |
3 | 1020211021001120100002 |
4 | 30031010330233001 |
5 | 203314200144131 |
6 | 10004154405345 |
7 | 642510511064 |
oct | 141504745701 |
9 | 36737046302 |
10 | 13104303041 |
11 | 5615045915 |
12 | 2658730855 |
13 | 130ab90c8b |
14 | 8c455a8db |
15 | 51a6a66cb |
hex | 30d13cbc1 |
13104303041 has 2 divisors, whose sum is σ = 13104303042. Its totient is φ = 13104303040.
The previous prime is 13104303013. The next prime is 13104303049. The reversal of 13104303041 is 14030340131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11577760000 + 1526543041 = 107600^2 + 39071^2 .
It is an emirp because it is prime and its reverse (14030340131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13104303041 - 210 = 13104302017 is a prime.
It is not a weakly prime, because it can be changed into another prime (13104303049) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552151520 + 6552151521.
It is an arithmetic number, because the mean of its divisors is an integer number (6552151521).
Almost surely, 213104303041 is an apocalyptic number.
It is an amenable number.
13104303041 is a deficient number, since it is larger than the sum of its proper divisors (1).
13104303041 is an equidigital number, since it uses as much as digits as its factorization.
13104303041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 13104303041 its reverse (14030340131), we get a palindrome (27134643172).
The spelling of 13104303041 in words is "thirteen billion, one hundred four million, three hundred three thousand, forty-one".
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