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13104322102121 is a prime number
BaseRepresentation
bin1011111010110001011001…
…1101101100001101101001
31201101202112201221102000112
42332230112131230031221
53204200122424231441
643512013101144105
72521520214005615
oct276542635541551
951352481842015
1013104322102121
1141a256a21a118
121577856b5b035
13740969a55523
143343770c4345
1517ad1806e4eb
hexbeb1676c369

13104322102121 has 2 divisors, whose sum is σ = 13104322102122. Its totient is φ = 13104322102120.

The previous prime is 13104322102037. The next prime is 13104322102147. The reversal of 13104322102121 is 12120122340131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7551531480025 + 5552790622096 = 2748005^2 + 2356436^2 .

It is a cyclic number.

It is not a de Polignac number, because 13104322102121 - 238 = 12829444195177 is a prime.

It is a super-2 number, since 2×131043221021212 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13104322102021) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552161051060 + 6552161051061.

It is an arithmetic number, because the mean of its divisors is an integer number (6552161051061).

Almost surely, 213104322102121 is an apocalyptic number.

It is an amenable number.

13104322102121 is a deficient number, since it is larger than the sum of its proper divisors (1).

13104322102121 is an equidigital number, since it uses as much as digits as its factorization.

13104322102121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 13104322102121 its reverse (12120122340131), we get a palindrome (25224444442252).

The spelling of 13104322102121 in words is "thirteen trillion, one hundred four billion, three hundred twenty-two million, one hundred two thousand, one hundred twenty-one".