Base | Representation |
---|---|
bin | 111101000001011001… |
… | …0010011010110111011 |
3 | 110112020121222111121011 |
4 | 1322002302103112323 |
5 | 4121334032242301 |
6 | 140111143254351 |
7 | 12316242122311 |
oct | 1720262232673 |
9 | 415217874534 |
10 | 131043243451 |
11 | 506365493aa |
12 | 2149214a3b7 |
13 | c485072953 |
14 | 64b1c720b1 |
15 | 361e737a51 |
hex | 1e82c935bb |
131043243451 has 2 divisors, whose sum is σ = 131043243452. Its totient is φ = 131043243450.
The previous prime is 131043243437. The next prime is 131043243467. The reversal of 131043243451 is 154342340131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131043243451 - 211 = 131043241403 is a prime.
It is not a weakly prime, because it can be changed into another prime (131043247451) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65521621725 + 65521621726.
It is an arithmetic number, because the mean of its divisors is an integer number (65521621726).
Almost surely, 2131043243451 is an apocalyptic number.
131043243451 is a deficient number, since it is larger than the sum of its proper divisors (1).
131043243451 is an equidigital number, since it uses as much as digits as its factorization.
131043243451 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 131043243451 its reverse (154342340131), we get a palindrome (285385583582).
The spelling of 131043243451 in words is "one hundred thirty-one billion, forty-three million, two hundred forty-three thousand, four hundred fifty-one".
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