Base | Representation |
---|---|
bin | 111101000001011001… |
… | …0010101100000010001 |
3 | 110112020121222221122201 |
4 | 1322002302111200101 |
5 | 4121334033032431 |
6 | 140111143403201 |
7 | 12316242160036 |
oct | 1720262254021 |
9 | 415217887581 |
10 | 131043252241 |
11 | 50636554a70 |
12 | 21492153501 |
13 | c485076955 |
14 | 64b1c7538d |
15 | 361e73a461 |
hex | 1e82c95811 |
131043252241 has 16 divisors (see below), whose sum is σ = 146525126400. Its totient is φ = 116174494080.
The previous prime is 131043252209. The next prime is 131043252247. The reversal of 131043252241 is 142252340131.
It is a cyclic number.
It is not a de Polignac number, because 131043252241 - 25 = 131043252209 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131043252247) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 314316 + ... + 600733.
It is an arithmetic number, because the mean of its divisors is an integer number (9157820400).
Almost surely, 2131043252241 is an apocalyptic number.
131043252241 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
131043252241 is a deficient number, since it is larger than the sum of its proper divisors (15481874159).
131043252241 is a wasteful number, since it uses less digits than its factorization.
131043252241 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 915384.
The product of its (nonzero) digits is 5760, while the sum is 28.
Adding to 131043252241 its reverse (142252340131), we get a palindrome (273295592372).
The spelling of 131043252241 in words is "one hundred thirty-one billion, forty-three million, two hundred fifty-two thousand, two hundred forty-one".
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