Base | Representation |
---|---|
bin | 111101000001011001… |
… | …0010101100000010111 |
3 | 110112020121222221122221 |
4 | 1322002302111200113 |
5 | 4121334033032442 |
6 | 140111143403211 |
7 | 12316242160045 |
oct | 1720262254027 |
9 | 415217887587 |
10 | 131043252247 |
11 | 50636554a76 |
12 | 21492153507 |
13 | c48507695b |
14 | 64b1c75395 |
15 | 361e73a467 |
hex | 1e82c95817 |
131043252247 has 2 divisors, whose sum is σ = 131043252248. Its totient is φ = 131043252246.
The previous prime is 131043252209. The next prime is 131043252253. The reversal of 131043252247 is 742252340131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131043252247 - 211 = 131043250199 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131043256247) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65521626123 + 65521626124.
It is an arithmetic number, because the mean of its divisors is an integer number (65521626124).
Almost surely, 2131043252247 is an apocalyptic number.
131043252247 is a deficient number, since it is larger than the sum of its proper divisors (1).
131043252247 is an equidigital number, since it uses as much as digits as its factorization.
131043252247 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 40320, while the sum is 34.
Adding to 131043252247 its reverse (742252340131), we get a palindrome (873295592378).
The spelling of 131043252247 in words is "one hundred thirty-one billion, forty-three million, two hundred fifty-two thousand, two hundred forty-seven".
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