13104331442541 has 24 divisors (see below), whose sum is σ = 19629956009664. Its totient is φ = 8736032930400.

The previous prime is 13104331442537. The next prime is 13104331442569. The reversal of 13104331442541 is 14524413340131.

13104331442541 is a `hidden beast` number, since 1 + 3 + 1 + 0 + 43 + 31 + 4 + 42 + 541 = 666.

It is not a de Polignac number, because 13104331442541 - 2² = 13104331442537 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13104331442496 and 13104331442505.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13104331442591) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 11226241 + ... + 12338441.

It is an arithmetic number, because the mean of its divisors is an integer number (817914833736).

Almost surely, 2^{13104331442541} is an apocalyptic number.

It is an amenable number.

13104331442541 is a deficient number, since it is larger than the sum of its proper divisors (6525624567123).

13104331442541 is an equidigital number, since it uses as much as digits as its factorization.

13104331442541 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1160703 (or 1160691 counting only the distinct ones).

The product of its (nonzero) digits is 69120, while the sum is 36.

Adding to 13104331442541 its reverse (14524413340131), we get a palindrome (27628744782672).

The spelling of 13104331442541 in words is "thirteen trillion, one hundred four billion, three hundred thirty-one million, four hundred forty-two thousand, five hundred forty-one".