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13104333415111 = 29034514065937
BaseRepresentation
bin1011111010110001011100…
…1000110110001011000111
31201101202120112020011112011
42332230113020312023013
53204200133323240421
643512014143435051
72521520412114241
oct276542710661307
951352515204464
1013104333415111
1141a25756467a4
12157785a8b5a87
1374096c1b68c3
143343787cb091
1517ad190564e1
hexbeb172362c7

13104333415111 has 4 divisors (see below), whose sum is σ = 13108847483952. Its totient is φ = 13099819346272.

The previous prime is 13104333415081. The next prime is 13104333415123. The reversal of 13104333415111 is 11151433340131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13104333415111 - 25 = 13104333415079 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13104333410111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2257030066 + ... + 2257035871.

It is an arithmetic number, because the mean of its divisors is an integer number (3277211870988).

Almost surely, 213104333415111 is an apocalyptic number.

13104333415111 is a deficient number, since it is larger than the sum of its proper divisors (4514068841).

13104333415111 is an equidigital number, since it uses as much as digits as its factorization.

13104333415111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4514068840.

The product of its (nonzero) digits is 6480, while the sum is 31.

Adding to 13104333415111 its reverse (11151433340131), we get a palindrome (24255766755242).

The spelling of 13104333415111 in words is "thirteen trillion, one hundred four billion, three hundred thirty-three million, four hundred fifteen thousand, one hundred eleven".

Divisors: 1 2903 4514065937 13104333415111