Base | Representation |
---|---|
bin | 1011111010110001011100… |
… | …1001010101001010011010 |
3 | 1201101202120112110121122022 |
4 | 2332230113021111022122 |
5 | 3204200133341321132 |
6 | 43512014150254442 |
7 | 2521520413153301 |
oct | 276542711251232 |
9 | 51352515417568 |
10 | 13104333542042 |
11 | 41a25757230a6 |
12 | 157785a957422 |
13 | 74096c22c602 |
14 | 334378821438 |
15 | 17ad1907de12 |
hex | beb1725529a |
13104333542042 has 32 divisors (see below), whose sum is σ = 19937786117760. Its totient is φ = 6459154341120.
The previous prime is 13104333542039. The next prime is 13104333542063. The reversal of 13104333542042 is 24024533340131.
It is a junction number, because it is equal to n+sod(n) for n = 13104333541993 and 13104333542011.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 43350542 + ... + 43651782.
It is an arithmetic number, because the mean of its divisors is an integer number (623055816180).
Almost surely, 213104333542042 is an apocalyptic number.
13104333542042 is a deficient number, since it is larger than the sum of its proper divisors (6833452575718).
13104333542042 is a wasteful number, since it uses less digits than its factorization.
13104333542042 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 302486.
The product of its (nonzero) digits is 103680, while the sum is 35.
Adding to 13104333542042 its reverse (24024533340131), we get a palindrome (37128866882173).
The spelling of 13104333542042 in words is "thirteen trillion, one hundred four billion, three hundred thirty-three million, five hundred forty-two thousand, forty-two".
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