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131043411354322 = 265521705677161
BaseRepresentation
bin11101110010111011101011…
…111110111110001011010010
3122011222121221122120000010201
4131302323223332332023102
5114134003401301314242
61142412302340245414
736413400615655645
oct3562735376761322
9564877848500121
10131043411354322
1138833220462155
12128451113a086a
1358174575a321c
14245076bc97a5c
151023b170434b7
hex772eebfbe2d2

131043411354322 has 4 divisors (see below), whose sum is σ = 196565117031486. Its totient is φ = 65521705677160.

The previous prime is 131043411354301. The next prime is 131043411354347. The reversal of 131043411354322 is 223453114340131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 120229711834761 + 10813699519561 = 10964931^2 + 3288419^2 .

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32760852838579 + ... + 32760852838582.

Almost surely, 2131043411354322 is an apocalyptic number.

131043411354322 is a deficient number, since it is larger than the sum of its proper divisors (65521705677164).

131043411354322 is an equidigital number, since it uses as much as digits as its factorization.

131043411354322 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 65521705677163.

The product of its (nonzero) digits is 103680, while the sum is 37.

Adding to 131043411354322 its reverse (223453114340131), we get a palindrome (354496525694453).

The spelling of 131043411354322 in words is "one hundred thirty-one trillion, forty-three billion, four hundred eleven million, three hundred fifty-four thousand, three hundred twenty-two".

Divisors: 1 2 65521705677161 131043411354322