Base | Representation |
---|---|
bin | 11101110010111011101011… |
… | …111110111110001011010010 |
3 | 122011222121221122120000010201 |
4 | 131302323223332332023102 |
5 | 114134003401301314242 |
6 | 1142412302340245414 |
7 | 36413400615655645 |
oct | 3562735376761322 |
9 | 564877848500121 |
10 | 131043411354322 |
11 | 38833220462155 |
12 | 128451113a086a |
13 | 58174575a321c |
14 | 245076bc97a5c |
15 | 1023b170434b7 |
hex | 772eebfbe2d2 |
131043411354322 has 4 divisors (see below), whose sum is σ = 196565117031486. Its totient is φ = 65521705677160.
The previous prime is 131043411354301. The next prime is 131043411354347. The reversal of 131043411354322 is 223453114340131.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 120229711834761 + 10813699519561 = 10964931^2 + 3288419^2 .
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32760852838579 + ... + 32760852838582.
Almost surely, 2131043411354322 is an apocalyptic number.
131043411354322 is a deficient number, since it is larger than the sum of its proper divisors (65521705677164).
131043411354322 is an equidigital number, since it uses as much as digits as its factorization.
131043411354322 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 65521705677163.
The product of its (nonzero) digits is 103680, while the sum is 37.
Adding to 131043411354322 its reverse (223453114340131), we get a palindrome (354496525694453).
The spelling of 131043411354322 in words is "one hundred thirty-one trillion, forty-three billion, four hundred eleven million, three hundred fifty-four thousand, three hundred twenty-two".
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