131043411354301 has 2 divisors, whose sum is σ = 131043411354302. Its totient is φ = 131043411354300.

The previous prime is 131043411354241. The next prime is 131043411354347. The reversal of 131043411354301 is 103453114340131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 121259959476100 + 9783451878201 = 11011810^2 + 3127851^2 .

It is an emirp because it is prime and its reverse (103453114340131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131043411354301 - 2¹³ = 131043411346109 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131043411351301) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65521705677150 + 65521705677151.

It is an arithmetic number, because the mean of its divisors is an integer number (65521705677151).

Almost surely, 2^{131043411354301} is an apocalyptic number.

It is an amenable number.

131043411354301 is a deficient number, since it is larger than the sum of its proper divisors (1).

131043411354301 is an equidigital number, since it uses as much as digits as its factorization.

131043411354301 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 25920, while the sum is 34.

Adding to 131043411354301 its reverse (103453114340131), we get a palindrome (234496525694432).

The spelling of 131043411354301 in words is "one hundred thirty-one trillion, forty-three billion, four hundred eleven million, three hundred fifty-four thousand, three hundred one".