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131044042551 = 343681347517
BaseRepresentation
bin111101000001011010…
…1010110011100110111
3110112020200111002202110
41322002311112130313
54121334233330201
6140111212342103
712316251661122
oct1720265263467
9415220432673
10131044042551
1150636a44814
1221492474933
13c4852925a6
1464b1ddd3b9
15361e8446d6
hex1e82d56737

131044042551 has 4 divisors (see below), whose sum is σ = 174725390072. Its totient is φ = 87362695032.

The previous prime is 131044042529. The next prime is 131044042561. The reversal of 131044042551 is 155240440131.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 131044042551 - 233 = 122454107959 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131044042561) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21840673756 + ... + 21840673761.

It is an arithmetic number, because the mean of its divisors is an integer number (43681347518).

Almost surely, 2131044042551 is an apocalyptic number.

131044042551 is a deficient number, since it is larger than the sum of its proper divisors (43681347521).

131044042551 is an equidigital number, since it uses as much as digits as its factorization.

131044042551 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 43681347520.

The product of its (nonzero) digits is 9600, while the sum is 30.

Adding to 131044042551 its reverse (155240440131), we get a palindrome (286284482682).

The spelling of 131044042551 in words is "one hundred thirty-one billion, forty-four million, forty-two thousand, five hundred fifty-one".

Divisors: 1 3 43681347517 131044042551