13104412003511 has 4 divisors (see below), whose sum is σ = 13198688349000. Its totient is φ = 13010135658024.

The previous prime is 13104412003451. The next prime is 13104412003517. The reversal of 13104412003511 is 11530021440131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13104412003511 - 2⁶ = 13104412003447 is a prime.

It is a super-2 number, since 2×13104412003511² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13104412003517) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 47138172536 + ... + 47138172813.

It is an arithmetic number, because the mean of its divisors is an integer number (3299672087250).

Almost surely, 2^{13104412003511} is an apocalyptic number.

13104412003511 is a deficient number, since it is larger than the sum of its proper divisors (94276345489).

13104412003511 is an equidigital number, since it uses as much as digits as its factorization.

13104412003511 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 94276345488.

The product of its (nonzero) digits is 1440, while the sum is 26.

Adding to 13104412003511 its reverse (11530021440131), we get a palindrome (24634433443642).

The spelling of 13104412003511 in words is "thirteen trillion, one hundred four billion, four hundred twelve million, three thousand, five hundred eleven".