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13104412003447 is a prime number
BaseRepresentation
bin1011111010110001101111…
…0100101000110001110111
31201101202210000002212110021
42332230123310220301313
53204200313433102242
643512030032110011
72521522355110612
oct276543364506167
951352700085407
1013104412003447
1141a2605a43336
121577881095307
1374098257158b
14334385007179
1517ad20dcbb67
hexbeb1bd28c77

13104412003447 has 2 divisors, whose sum is σ = 13104412003448. Its totient is φ = 13104412003446.

The previous prime is 13104412003429. The next prime is 13104412003451. The reversal of 13104412003447 is 74430021440131.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13104412003447 is a prime.

It is a super-2 number, since 2×131044120034472 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13104412004447) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552206001723 + 6552206001724.

It is an arithmetic number, because the mean of its divisors is an integer number (6552206001724).

Almost surely, 213104412003447 is an apocalyptic number.

13104412003447 is a deficient number, since it is larger than the sum of its proper divisors (1).

13104412003447 is an equidigital number, since it uses as much as digits as its factorization.

13104412003447 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 32256, while the sum is 34.

Adding to 13104412003447 its reverse (74430021440131), we get a palindrome (87534433443578).

The spelling of 13104412003447 in words is "thirteen trillion, one hundred four billion, four hundred twelve million, three thousand, four hundred forty-seven".