13104413144453 has 4 divisors (see below), whose sum is σ = 13105801480320. Its totient is φ = 13103024808588.

The previous prime is 13104413144413. The next prime is 13104413144461. The reversal of 13104413144453 is 35444131440131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13104413144453 - 2¹⁰ = 13104413143429 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13104413144413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 694153775 + ... + 694172652.

It is an arithmetic number, because the mean of its divisors is an integer number (3276450370080).

Almost surely, 2^{13104413144453} is an apocalyptic number.

It is an amenable number.

13104413144453 is a deficient number, since it is larger than the sum of its proper divisors (1388335867).

13104413144453 is an equidigital number, since it uses as much as digits as its factorization.

13104413144453 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1388335866.

The product of its (nonzero) digits is 138240, while the sum is 38.

Adding to 13104413144453 its reverse (35444131440131), we get a palindrome (48548544584584).

The spelling of 13104413144453 in words is "thirteen trillion, one hundred four billion, four hundred thirteen million, one hundred forty-four thousand, four hundred fifty-three".