Base | Representation |
---|---|
bin | 11101110010111100011011… |
… | …000111111100001000101111 |
3 | 122011222200222202201212200000 |
4 | 131302330123013330020233 |
5 | 114134012011233000130 |
6 | 1142412513031435343 |
7 | 36413426331226551 |
oct | 3562743307741057 |
9 | 564880882655600 |
10 | 131044202234415 |
11 | 38833596934068 |
12 | 128452b2225b53 |
13 | 58175523b2002 |
14 | 2450804d2b4d1 |
15 | 1023b616b8260 |
hex | 772f1b1fc22f |
131044202234415 has 48 divisors (see below), whose sum is σ = 235809558784800. Its totient is φ = 69815008899072.
The previous prime is 131044202234401. The next prime is 131044202234417. The reversal of 131044202234415 is 514432202440131.
131044202234415 is a `hidden beast` number, since 1 + 3 + 1 + 0 + 4 + 4 + 2 + 0 + 2 + 234 + 415 = 666.
It is not a de Polignac number, because 131044202234415 - 210 = 131044202233391 is a prime.
It is a super-2 number, since 2×1310442022344152 (a number of 29 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 131044202234415.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131044202234417) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 56920410 + ... + 59177879.
It is an arithmetic number, because the mean of its divisors is an integer number (4912699141350).
Almost surely, 2131044202234415 is an apocalyptic number.
131044202234415 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
131044202234415 is a deficient number, since it is larger than the sum of its proper divisors (104765356550385).
131044202234415 is an equidigital number, since it uses as much as digits as its factorization.
131044202234415 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 116099238 (or 116099226 counting only the distinct ones).
The product of its (nonzero) digits is 92160, while the sum is 36.
Adding to 131044202234415 its reverse (514432202440131), we get a palindrome (645476404674546).
The spelling of 131044202234415 in words is "one hundred thirty-one trillion, forty-four billion, two hundred two million, two hundred thirty-four thousand, four hundred fifteen".
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