Base | Representation |
---|---|
bin | 11101110010111100011110… |
… | …000001111110011010000001 |
3 | 122011222201010011111112220021 |
4 | 131302330132001332122001 |
5 | 114134012111224034442 |
6 | 1142412521533013441 |
7 | 36413430462603550 |
oct | 3562743601763201 |
9 | 564881104445807 |
10 | 131044251002497 |
11 | 38833611413268 |
12 | 12845306624281 |
13 | 581755c528771 |
14 | 245080b5c3d97 |
15 | 1023b65aece67 |
hex | 772f1e07e681 |
131044251002497 has 16 divisors (see below), whose sum is σ = 156334074510592. Its totient is φ = 107496265129920.
The previous prime is 131044251002387. The next prime is 131044251002573. The reversal of 131044251002497 is 794200152440131.
It is a cyclic number.
It is not a de Polignac number, because 131044251002497 - 211 = 131044251000449 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131044251002297) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4147216653 + ... + 4147248250.
It is an arithmetic number, because the mean of its divisors is an integer number (9770879656912).
Almost surely, 2131044251002497 is an apocalyptic number.
It is an amenable number.
131044251002497 is a deficient number, since it is larger than the sum of its proper divisors (25289823508095).
131044251002497 is an equidigital number, since it uses as much as digits as its factorization.
131044251002497 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8294465008.
The product of its (nonzero) digits is 241920, while the sum is 43.
The spelling of 131044251002497 in words is "one hundred thirty-one trillion, forty-four billion, two hundred fifty-one million, two thousand, four hundred ninety-seven".
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