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131044251002573 is a prime number
BaseRepresentation
bin11101110010111100011110…
…000001111110011011001101
3122011222201010011111120000002
4131302330132001332123031
5114134012111224040243
61142412521533014045
736413430462604016
oct3562743601763315
9564881104446002
10131044251002573
1138833611413327
1212845306624325
13581755c5287cc
14245080b5c400d
151023b65aeceb8
hex772f1e07e6cd

131044251002573 has 2 divisors, whose sum is σ = 131044251002574. Its totient is φ = 131044251002572.

The previous prime is 131044251002387. The next prime is 131044251002591. The reversal of 131044251002573 is 375200152440131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 126334947373924 + 4709303628649 = 11239882^2 + 2170093^2 .

It is a cyclic number.

It is not a de Polignac number, because 131044251002573 - 214 = 131044250986189 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131044251502573) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65522125501286 + 65522125501287.

It is an arithmetic number, because the mean of its divisors is an integer number (65522125501287).

Almost surely, 2131044251002573 is an apocalyptic number.

It is an amenable number.

131044251002573 is a deficient number, since it is larger than the sum of its proper divisors (1).

131044251002573 is an equidigital number, since it uses as much as digits as its factorization.

131044251002573 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 100800, while the sum is 38.

The spelling of 131044251002573 in words is "one hundred thirty-one trillion, forty-four billion, two hundred fifty-one million, two thousand, five hundred seventy-three".