131044251120281 has 2 divisors, whose sum is σ = 131044251120282. Its totient is φ = 131044251120280.

The previous prime is 131044251120197. The next prime is 131044251120353. The reversal of 131044251120281 is 182021152440131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 124142381286400 + 6901869833881 = 11141920^2 + 2627141^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131044251120281 is a prime.

It is a super-2 number, since 2×131044251120281² (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (131044251110281) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65522125560140 + 65522125560141.

It is an arithmetic number, because the mean of its divisors is an integer number (65522125560141).

Almost surely, 2^{131044251120281} is an apocalyptic number.

It is an amenable number.

131044251120281 is a deficient number, since it is larger than the sum of its proper divisors (1).

131044251120281 is an equidigital number, since it uses as much as digits as its factorization.

131044251120281 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15360, while the sum is 35.

The spelling of 131044251120281 in words is "one hundred thirty-one trillion, forty-four billion, two hundred fifty-one million, one hundred twenty thousand, two hundred eighty-one".