Base | Representation |
---|---|
bin | 11101110010111100100010… |
… | …111000001011011010010010 |
3 | 122011222201022211111221002112 |
4 | 131302330202320023122102 |
5 | 114134012243033223102 |
6 | 1142412533555545322 |
7 | 36413432501026154 |
oct | 3562744270133222 |
9 | 564881284457075 |
10 | 131044332320402 |
11 | 38833653304646 |
12 | 128453298bb242 |
13 | 581757332a977 |
14 | 2450818310ad4 |
15 | 1023b6cd12252 |
hex | 772f22e0b692 |
131044332320402 has 4 divisors (see below), whose sum is σ = 196566498480606. Its totient is φ = 65522166160200.
The previous prime is 131044332320371. The next prime is 131044332320443. The reversal of 131044332320402 is 204023233440131.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 96202925439481 + 34841406880921 = 9808309^2 + 5902661^2 .
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32761083080099 + ... + 32761083080102.
Almost surely, 2131044332320402 is an apocalyptic number.
131044332320402 is a deficient number, since it is larger than the sum of its proper divisors (65522166160204).
131044332320402 is an equidigital number, since it uses as much as digits as its factorization.
131044332320402 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 65522166160203.
The product of its (nonzero) digits is 41472, while the sum is 32.
Adding to 131044332320402 its reverse (204023233440131), we get a palindrome (335067565760533).
The spelling of 131044332320402 in words is "one hundred thirty-one trillion, forty-four billion, three hundred thirty-two million, three hundred twenty thousand, four hundred two".
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