Base | Representation |
---|---|
bin | 1011111010110001110101… |
… | …1111111110001011011001 |
3 | 1201101202211222001101020112 |
4 | 2332230131133332023121 |
5 | 3204200343133444010 |
6 | 43512032515134105 |
7 | 2521523146220060 |
oct | 276543537761331 |
9 | 51352758041215 |
10 | 13104440140505 |
11 | 41a261a9110aa |
12 | 157788a5a4335 |
13 | 74098834361c |
14 | 334388a4d1d7 |
15 | 17ad235d8a05 |
hex | beb1d7fe2d9 |
13104440140505 has 16 divisors (see below), whose sum is σ = 17980803118080. Its totient is φ = 8981402062272.
The previous prime is 13104440140481. The next prime is 13104440140507. The reversal of 13104440140505 is 50504104440131.
It is a cyclic number.
It is not a de Polignac number, because 13104440140505 - 216 = 13104440074969 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13104440140507) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 93673865 + ... + 93813654.
It is an arithmetic number, because the mean of its divisors is an integer number (1123800194880).
Almost surely, 213104440140505 is an apocalyptic number.
It is an amenable number.
13104440140505 is a deficient number, since it is larger than the sum of its proper divisors (4876362977575).
13104440140505 is a wasteful number, since it uses less digits than its factorization.
13104440140505 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 187489528.
The product of its (nonzero) digits is 19200, while the sum is 32.
Adding to 13104440140505 its reverse (50504104440131), we get a palindrome (63608544580636).
The spelling of 13104440140505 in words is "thirteen trillion, one hundred four billion, four hundred forty million, one hundred forty thousand, five hundred five".
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