Base | Representation |
---|---|
bin | 11000011010001010… |
… | …11111001110001101 |
3 | 1020211021022202002221 |
4 | 30031011133032031 |
5 | 203314214204201 |
6 | 10004201415341 |
7 | 642511636654 |
oct | 141505371615 |
9 | 36737282087 |
10 | 13104444301 |
11 | 5615131a63 |
12 | 265879a551 |
13 | 130ac10370 |
14 | 8c459619b |
15 | 51a6d34a1 |
hex | 30d15f38d |
13104444301 has 16 divisors (see below), whose sum is σ = 14157990000. Its totient is φ = 12057477120.
The previous prime is 13104444263. The next prime is 13104444319. The reversal of 13104444301 is 10344440131.
It can be written as a sum of positive squares in 8 ways, for example, as 1654374276 + 11450070025 = 40674^2 + 107005^2 .
It is not a de Polignac number, because 13104444301 - 29 = 13104443789 is a prime.
It is a super-2 number, since 2×131044443012 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13104444361) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 9627861 + ... + 9629221.
It is an arithmetic number, because the mean of its divisors is an integer number (884874375).
Almost surely, 213104444301 is an apocalyptic number.
It is an amenable number.
13104444301 is a deficient number, since it is larger than the sum of its proper divisors (1053545699).
13104444301 is a wasteful number, since it uses less digits than its factorization.
13104444301 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3216.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 13104444301 its reverse (10344440131), we get a palindrome (23448884432).
The spelling of 13104444301 in words is "thirteen billion, one hundred four million, four hundred forty-four thousand, three hundred one".
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