131044443354541 has 4 divisors (see below), whose sum is σ = 135271683462784. Its totient is φ = 126817203246300.

The previous prime is 131044443354497. The next prime is 131044443354641. The reversal of 131044443354541 is 145453344440131.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131044443354541 - 2⁹ = 131044443354029 is a prime.

It is a super-2 number, since 2×131044443354541² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131044443354491 and 131044443354500.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131044443354641) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2113620054075 + ... + 2113620054136.

It is an arithmetic number, because the mean of its divisors is an integer number (33817920865696).

Almost surely, 2^{131044443354541} is an apocalyptic number.

It is an amenable number.

131044443354541 is a deficient number, since it is larger than the sum of its proper divisors (4227240108243).

131044443354541 is an equidigital number, since it uses as much as digits as its factorization.

131044443354541 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4227240108242.

The product of its (nonzero) digits is 2764800, while the sum is 46.

Adding to 131044443354541 its reverse (145453344440131), we get a palindrome (276497787794672).

The spelling of 131044443354541 in words is "one hundred thirty-one trillion, forty-four billion, four hundred forty-three million, three hundred fifty-four thousand, five hundred forty-one".