Base | Representation |
---|---|
bin | 1011111010110001110111… |
… | …0000110011110100100111 |
3 | 1201101202212021100122011010 |
4 | 2332230131300303310213 |
5 | 3204200400301221120 |
6 | 43512033153513303 |
7 | 2521523231563005 |
oct | 276543560636447 |
9 | 51352767318133 |
10 | 13104444554535 |
11 | 41a2622356464 |
12 | 157788bb72833 |
13 | 74098922a789 |
14 | 33438947ba75 |
15 | 17ad23bab7e0 |
hex | beb1dc33d27 |
13104444554535 has 32 divisors (see below), whose sum is σ = 20982908943360. Its totient is φ = 6983772453248.
The previous prime is 13104444554521. The next prime is 13104444554549. The reversal of 13104444554535 is 53545544440131.
It is an interprime number because it is at equal distance from previous prime (13104444554521) and next prime (13104444554549).
It is a cyclic number.
It is not a de Polignac number, because 13104444554535 - 25 = 13104444554503 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 192059656 + ... + 192127874.
It is an arithmetic number, because the mean of its divisors is an integer number (655715904480).
Almost surely, 213104444554535 is an apocalyptic number.
13104444554535 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13104444554535 is a deficient number, since it is larger than the sum of its proper divisors (7878464388825).
13104444554535 is a wasteful number, since it uses less digits than its factorization.
13104444554535 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 77687.
The product of its (nonzero) digits is 5760000, while the sum is 48.
Adding to 13104444554535 its reverse (53545544440131), we get a palindrome (66649988994666).
The spelling of 13104444554535 in words is "thirteen trillion, one hundred four billion, four hundred forty-four million, five hundred fifty-four thousand, five hundred thirty-five".
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