Base | Representation |
---|---|
bin | 1011111010110010000111… |
… | …1010100100100000101011 |
3 | 1201101210001010110010010011 |
4 | 2332230201322210200223 |
5 | 3204201021120101443 |
6 | 43512044123032351 |
7 | 2521525036003342 |
oct | 276544172444053 |
9 | 51353033403104 |
10 | 13104514222123 |
11 | 41a265870a785 |
12 | 15778ab36b6b7 |
13 | 74099a7b0bbc |
14 | 334394814b59 |
15 | 17ad29d6db9d |
hex | beb21ea482b |
13104514222123 has 2 divisors, whose sum is σ = 13104514222124. Its totient is φ = 13104514222122.
The previous prime is 13104514222043. The next prime is 13104514222147. The reversal of 13104514222123 is 32122241540131.
13104514222123 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13104514222123 is a prime.
It is not a weakly prime, because it can be changed into another prime (13104514222193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552257111061 + 6552257111062.
It is an arithmetic number, because the mean of its divisors is an integer number (6552257111062).
Almost surely, 213104514222123 is an apocalyptic number.
13104514222123 is a deficient number, since it is larger than the sum of its proper divisors (1).
13104514222123 is an equidigital number, since it uses as much as digits as its factorization.
13104514222123 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11520, while the sum is 31.
Adding to 13104514222123 its reverse (32122241540131), we get a palindrome (45226755762254).
The spelling of 13104514222123 in words is "thirteen trillion, one hundred four billion, five hundred fourteen million, two hundred twenty-two thousand, one hundred twenty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •