Base | Representation |
---|---|
bin | 1011111010110010001001… |
… | …0000110001001100010011 |
3 | 1201101210001112101202102211 |
4 | 2332230202100301030103 |
5 | 3204201024112304420 |
6 | 43512044451452551 |
7 | 2521525136320600 |
oct | 276544220611423 |
9 | 51353045352384 |
10 | 13104520041235 |
11 | 41a2660a24767 |
12 | 15778b12b7157 |
13 | 74099ba6a76c |
14 | 3343954cb6a7 |
15 | 17ad2a61ce5a |
hex | beb22431313 |
13104520041235 has 96 divisors (see below), whose sum is σ = 18584545851648. Its totient is φ = 8843821056000.
The previous prime is 13104520041211. The next prime is 13104520041257. The reversal of 13104520041235 is 53214002540131.
It is not a de Polignac number, because 13104520041235 - 223 = 13104511652627 is a prime.
It is a super-2 number, since 2×131045200412352 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13104520041197 and 13104520041206.
It is an unprimeable number.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 4586809927 + ... + 4586812783.
It is an arithmetic number, because the mean of its divisors is an integer number (193589019288).
Almost surely, 213104520041235 is an apocalyptic number.
13104520041235 is a deficient number, since it is larger than the sum of its proper divisors (5480025810413).
13104520041235 is a wasteful number, since it uses less digits than its factorization.
13104520041235 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3981 (or 3974 counting only the distinct ones).
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 13104520041235 its reverse (53214002540131), we get a palindrome (66318522581366).
The spelling of 13104520041235 in words is "thirteen trillion, one hundred four billion, five hundred twenty million, forty-one thousand, two hundred thirty-five".
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