Base | Representation |
---|---|
bin | 1011111010110010001001… |
… | …1001001000000011010011 |
3 | 1201101210001200112001121222 |
4 | 2332230202121020003103 |
5 | 3204201030142411034 |
6 | 43512045010435255 |
7 | 2521525164043661 |
oct | 276544231100323 |
9 | 51353050461558 |
10 | 13104522232019 |
11 | 41a2662190729 |
12 | 15778b1b92b2b |
13 | 74099c35699a |
14 | 3343958dbc31 |
15 | 17ad2a90212e |
hex | beb226480d3 |
13104522232019 has 2 divisors, whose sum is σ = 13104522232020. Its totient is φ = 13104522232018.
The previous prime is 13104522232007. The next prime is 13104522232033. The reversal of 13104522232019 is 91023222540131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13104522232019 - 232 = 13100227264723 is a prime.
It is a super-2 number, since 2×131045222320192 (a number of 27 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 13104522232019.
It is not a weakly prime, because it can be changed into another prime (13104522232069) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552261116009 + 6552261116010.
It is an arithmetic number, because the mean of its divisors is an integer number (6552261116010).
Almost surely, 213104522232019 is an apocalyptic number.
13104522232019 is a deficient number, since it is larger than the sum of its proper divisors (1).
13104522232019 is an equidigital number, since it uses as much as digits as its factorization.
13104522232019 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 25920, while the sum is 35.
The spelling of 13104522232019 in words is "thirteen trillion, one hundred four billion, five hundred twenty-two million, two hundred thirty-two thousand, nineteen".
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