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13104524332111 = 71184570765241
BaseRepresentation
bin1011111010110010001010…
…0001001000110001001111
31201101210001211110202102011
42332230202201020301033
53204201031212111421
643512045123442051
72521525220641462
oct276544241106117
951353054422364
1013104524332111
1141a2663395543
1215778b2826327
1374099c910844
14334395cc72d9
1517ad2abb94e1
hexbeb22848c4f

13104524332111 has 4 divisors (see below), whose sum is σ = 13289095097424. Its totient is φ = 12919953566800.

The previous prime is 13104524332073. The next prime is 13104524332169. The reversal of 13104524332111 is 11123342540131.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13104524332111 - 229 = 13103987461199 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13104524332171) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 92285382550 + ... + 92285382691.

It is an arithmetic number, because the mean of its divisors is an integer number (3322273774356).

Almost surely, 213104524332111 is an apocalyptic number.

13104524332111 is a deficient number, since it is larger than the sum of its proper divisors (184570765313).

13104524332111 is an equidigital number, since it uses as much as digits as its factorization.

13104524332111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 184570765312.

The product of its (nonzero) digits is 8640, while the sum is 31.

Adding to 13104524332111 its reverse (11123342540131), we get a palindrome (24227866872242).

The spelling of 13104524332111 in words is "thirteen trillion, one hundred four billion, five hundred twenty-four million, three hundred thirty-two thousand, one hundred eleven".

Divisors: 1 71 184570765241 13104524332111