Base | Representation |
---|---|
bin | 1011111010110010001010… |
… | …0100000111110010100101 |
3 | 1201101210001212221111200202 |
4 | 2332230202210013302211 |
5 | 3204201031412131113 |
6 | 43512045152320245 |
7 | 2521525230410546 |
oct | 276544244076245 |
9 | 51353055844622 |
10 | 13104525114533 |
11 | 41a266387a376 |
12 | 15778b2b43085 |
13 | 74099cb25a08 |
14 | 33439604c4cd |
15 | 17ad2acc1258 |
hex | beb22907ca5 |
13104525114533 has 4 divisors (see below), whose sum is σ = 13112376838860. Its totient is φ = 13096673390208.
The previous prime is 13104525114497. The next prime is 13104525114563. The reversal of 13104525114533 is 33541152540131.
13104525114533 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 8242508934529 + 4862016180004 = 2870977^2 + 2204998^2 .
It is a cyclic number.
It is not a de Polignac number, because 13104525114533 - 28 = 13104525114277 is a prime.
It is a super-2 number, since 2×131045251145332 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13104525114563) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3925859660 + ... + 3925862997.
It is an arithmetic number, because the mean of its divisors is an integer number (3278094209715).
Almost surely, 213104525114533 is an apocalyptic number.
It is an amenable number.
13104525114533 is a deficient number, since it is larger than the sum of its proper divisors (7851724327).
13104525114533 is an equidigital number, since it uses as much as digits as its factorization.
13104525114533 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7851724326.
The product of its (nonzero) digits is 108000, while the sum is 38.
Adding to 13104525114533 its reverse (33541152540131), we get a palindrome (46645677654664).
The spelling of 13104525114533 in words is "thirteen trillion, one hundred four billion, five hundred twenty-five million, one hundred fourteen thousand, five hundred thirty-three".
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