13104551350343 has 8 divisors (see below), whose sum is σ = 13161897875280. Its totient is φ = 13047205881600.

The previous prime is 13104551350339. The next prime is 13104551350391. The reversal of 13104551350343 is 34305315540131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13104551350343 - 2² = 13104551350339 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13104551350297 and 13104551350306.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13104551350333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 34715768 + ... + 35091218.

It is an arithmetic number, because the mean of its divisors is an integer number (1645237234410).

Almost surely, 2^{13104551350343} is an apocalyptic number.

13104551350343 is a deficient number, since it is larger than the sum of its proper divisors (57346524937).

13104551350343 is a wasteful number, since it uses less digits than its factorization.

13104551350343 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 528097.

The product of its (nonzero) digits is 162000, while the sum is 38.

Adding to 13104551350343 its reverse (34305315540131), we get a palindrome (47409866890474).

The spelling of 13104551350343 in words is "thirteen trillion, one hundred four billion, five hundred fifty-one million, three hundred fifty thousand, three hundred forty-three".