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13104553450404 = 2231384003547759
BaseRepresentation
bin1011111010110010010001…
…0000001101101110100100
31201101210010212021010012110
42332230210100031232210
53204201111140403104
643512052043521020
72521526023305453
oct276544420155644
951353125233173
1013104553450404
1141a2678873549
121577900529170
137409a59673c0
14334399b06b9a
1517ad2d51be89
hexbeb2440dba4

13104553450404 has 24 divisors (see below), whose sum is σ = 32929390721920. Its totient is φ = 4032170292384.

The previous prime is 13104553450379. The next prime is 13104553450421. The reversal of 13104553450404 is 40405435540131.

It is a super-2 number, since 2×131045534504042 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (39).

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 42001773724 + ... + 42001774035.

Almost surely, 213104553450404 is an apocalyptic number.

It is an amenable number.

13104553450404 is an abundant number, since it is smaller than the sum of its proper divisors (19824837271516).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13104553450404 is a wasteful number, since it uses less digits than its factorization.

13104553450404 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 84003547779 (or 84003547777 counting only the distinct ones).

The product of its (nonzero) digits is 288000, while the sum is 39.

Adding to 13104553450404 its reverse (40405435540131), we get a palindrome (53509988990535).

The spelling of 13104553450404 in words is "thirteen trillion, one hundred four billion, five hundred fifty-three million, four hundred fifty thousand, four hundred four".

Divisors: 1 2 3 4 6 12 13 26 39 52 78 156 84003547759 168007095518 252010643277 336014191036 504021286554 1008042573108 1092046120867 2184092241734 3276138362601 4368184483468 6552276725202 13104553450404