1310494319857 has 2 divisors, whose sum is σ = 1310494319858. Its totient is φ = 1310494319856.

The previous prime is 1310494319833. The next prime is 1310494319863. The reversal of 1310494319857 is 7589134940131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 698421232656 + 612073087201 = 835716^2 + 782351^2 .

It is a cyclic number.

It is not a de Polignac number, because 1310494319857 - 2¹¹ = 1310494317809 is a prime.

It is a super-2 number, since 2×1310494319857² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1310494319798 and 1310494319807.

It is not a weakly prime, because it can be changed into another prime (1310494619857) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655247159928 + 655247159929.

It is an arithmetic number, because the mean of its divisors is an integer number (655247159929).

Almost surely, 2^{1310494319857} is an apocalyptic number.

It is an amenable number.

1310494319857 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310494319857 is an equidigital number, since it uses as much as digits as its factorization.

1310494319857 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3265920, while the sum is 55.

The spelling of 1310494319857 in words is "one trillion, three hundred ten billion, four hundred ninety-four million, three hundred nineteen thousand, eight hundred fifty-seven".