Base | Representation |
---|---|
bin | 11101110011000010010000… |
… | …100000000100011000101101 |
3 | 122012000022011022222120101112 |
4 | 131303002100200010120231 |
5 | 114134112323403224404 |
6 | 1142415430403521405 |
7 | 36414040504252520 |
oct | 3563022040043055 |
9 | 565008138876345 |
10 | 131050466461229 |
11 | 38836210925417 |
12 | 12846560089265 |
13 | 5818010131bb3 |
14 | 2450c3ac7abb7 |
15 | 1023dcb5e556e |
hex | 77309080462d |
131050466461229 has 4 divisors (see below), whose sum is σ = 149771961669984. Its totient is φ = 112328971252476.
The previous prime is 131050466461157. The next prime is 131050466461283. The reversal of 131050466461229 is 922164664050131.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131050466461229 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131050466466229) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9360747604367 + ... + 9360747604380.
It is an arithmetic number, because the mean of its divisors is an integer number (37442990417496).
Almost surely, 2131050466461229 is an apocalyptic number.
It is an amenable number.
131050466461229 is a deficient number, since it is larger than the sum of its proper divisors (18721495208755).
131050466461229 is an equidigital number, since it uses as much as digits as its factorization.
131050466461229 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18721495208754.
The product of its (nonzero) digits is 1866240, while the sum is 50.
The spelling of 131050466461229 in words is "one hundred thirty-one trillion, fifty billion, four hundred sixty-six million, four hundred sixty-one thousand, two hundred twenty-nine".
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