Base | Representation |
---|---|
bin | 11101110011000010010000… |
… | …100000000100011001100011 |
3 | 122012000022011022222120110112 |
4 | 131303002100200010121203 |
5 | 114134112323403230113 |
6 | 1142415430403521535 |
7 | 36414040504252625 |
oct | 3563022040043143 |
9 | 565008138876415 |
10 | 131050466461283 |
11 | 38836210925466 |
12 | 128465600892ab |
13 | 5818010131c25 |
14 | 2450c3ac7ac15 |
15 | 1023dcb5e55a8 |
hex | 773090804663 |
131050466461283 has 2 divisors, whose sum is σ = 131050466461284. Its totient is φ = 131050466461282.
The previous prime is 131050466461157. The next prime is 131050466461337. The reversal of 131050466461283 is 382164664050131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131050466461283 - 212 = 131050466457187 is a prime.
It is not a weakly prime, because it can be changed into another prime (131050466761283) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65525233230641 + 65525233230642.
It is an arithmetic number, because the mean of its divisors is an integer number (65525233230642).
Almost surely, 2131050466461283 is an apocalyptic number.
131050466461283 is a deficient number, since it is larger than the sum of its proper divisors (1).
131050466461283 is an equidigital number, since it uses as much as digits as its factorization.
131050466461283 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2488320, while the sum is 50.
The spelling of 131050466461283 in words is "one hundred thirty-one trillion, fifty billion, four hundred sixty-six million, four hundred sixty-one thousand, two hundred eighty-three".
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