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1310511004249 is a prime number
BaseRepresentation
bin10011000100100000100…
…010101111101001011001
311122021122202122210101211
4103010200202233221121
5132432411304113444
62442012422543121
7163452453511546
oct23044042575131
94567582583354
101310511004249
1146586a32a267
12191b9b597aa1
1396771920695
1447601529bcd
1524151ac1c34
hex131208afa59

1310511004249 has 2 divisors, whose sum is σ = 1310511004250. Its totient is φ = 1310511004248.

The previous prime is 1310511004207. The next prime is 1310511004259. The reversal of 1310511004249 is 9424001150131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1303627315225 + 6883689024 = 1141765^2 + 82968^2 .

It is a cyclic number.

It is not a de Polignac number, because 1310511004249 - 215 = 1310510971481 is a prime.

It is a super-3 number, since 3×13105110042493 (a number of 37 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1310511004249.

It is not a weakly prime, because it can be changed into another prime (1310511004259) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655255502124 + 655255502125.

It is an arithmetic number, because the mean of its divisors is an integer number (655255502125).

Almost surely, 21310511004249 is an apocalyptic number.

It is an amenable number.

1310511004249 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310511004249 is an equidigital number, since it uses as much as digits as its factorization.

1310511004249 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4320, while the sum is 31.

The spelling of 1310511004249 in words is "one trillion, three hundred ten billion, five hundred eleven million, four thousand, two hundred forty-nine".