Base | Representation |
---|---|
bin | 11101110011000011000100… |
… | …001110110100010101001011 |
3 | 122012000101101211002002210112 |
4 | 131303003010032310111023 |
5 | 114134121113043314001 |
6 | 1142420052445504535 |
7 | 36414101143236053 |
oct | 3563030416642513 |
9 | 565011354062715 |
10 | 131051334354251 |
11 | 38836616818283 |
12 | 1284676287214b |
13 | 581811ab9656c |
14 | 2450cc023a563 |
15 | 1023e2c8cdcbb |
hex | 7730c43b454b |
131051334354251 has 2 divisors, whose sum is σ = 131051334354252. Its totient is φ = 131051334354250.
The previous prime is 131051334354139. The next prime is 131051334354289. The reversal of 131051334354251 is 152453433150131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131051334354251 - 246 = 60682590176587 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 131051334354199 and 131051334354208.
It is not a weakly prime, because it can be changed into another prime (131051334354751) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65525667177125 + 65525667177126.
It is an arithmetic number, because the mean of its divisors is an integer number (65525667177126).
Almost surely, 2131051334354251 is an apocalyptic number.
131051334354251 is a deficient number, since it is larger than the sum of its proper divisors (1).
131051334354251 is an equidigital number, since it uses as much as digits as its factorization.
131051334354251 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 324000, while the sum is 41.
The spelling of 131051334354251 in words is "one hundred thirty-one trillion, fifty-one billion, three hundred thirty-four million, three hundred fifty-four thousand, two hundred fifty-one".
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