Base | Representation |
---|---|
bin | 111101000001101100… |
… | …0101011111001011011 |
3 | 110112021022220201001020 |
4 | 1322003120223321123 |
5 | 4121344121233220 |
6 | 140112143053523 |
7 | 12316423500453 |
oct | 1720330537133 |
9 | 415238821036 |
10 | 131053305435 |
11 | 506411a1098 |
12 | 214955a12a3 |
13 | c4871867a0 |
14 | 64b3330d63 |
15 | 3620574040 |
hex | 1e8362be5b |
131053305435 has 64 divisors (see below), whose sum is σ = 231166172160. Its totient is φ = 63004147200.
The previous prime is 131053305433. The next prime is 131053305451. The reversal of 131053305435 is 534503350131.
It is a happy number.
It is not a de Polignac number, because 131053305435 - 21 = 131053305433 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 131053305396 and 131053305405.
It is not an unprimeable number, because it can be changed into a prime (131053305433) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1699537 + ... + 1774973.
It is an arithmetic number, because the mean of its divisors is an integer number (3611971440).
Almost surely, 2131053305435 is an apocalyptic number.
131053305435 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
131053305435 is a deficient number, since it is larger than the sum of its proper divisors (100112866725).
131053305435 is a wasteful number, since it uses less digits than its factorization.
131053305435 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 75668.
The product of its (nonzero) digits is 40500, while the sum is 33.
Adding to 131053305435 its reverse (534503350131), we get a palindrome (665556655566).
The spelling of 131053305435 in words is "one hundred thirty-one billion, fifty-three million, three hundred five thousand, four hundred thirty-five".
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