Base | Representation |
---|---|
bin | 1011111010110101001010… |
… | …1011010011000011100111 |
3 | 1201101212011010210212210220 |
4 | 2332231102223103003213 |
5 | 3204204210032131210 |
6 | 43512301225215423 |
7 | 2521554231401130 |
oct | 276552253230347 |
9 | 51355133725726 |
10 | 13105332302055 |
11 | 41a2a3847a2a4 |
12 | 1577a99331573 |
13 | 740a9b124276 |
14 | 334431328c87 |
15 | 17ad76ab7c70 |
hex | beb52ad30e7 |
13105332302055 has 32 divisors (see below), whose sum is σ = 24737069641728. Its totient is φ = 5797750694400.
The previous prime is 13105332302039. The next prime is 13105332302063. The reversal of 13105332302055 is 55020323350131.
It is not a de Polignac number, because 13105332302055 - 24 = 13105332302039 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2013104626 + ... + 2013111135.
It is an arithmetic number, because the mean of its divisors is an integer number (773033426304).
Almost surely, 213105332302055 is an apocalyptic number.
13105332302055 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13105332302055 is a deficient number, since it is larger than the sum of its proper divisors (11631737339673).
13105332302055 is a wasteful number, since it uses less digits than its factorization.
13105332302055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4026215807.
The product of its (nonzero) digits is 40500, while the sum is 33.
Adding to 13105332302055 its reverse (55020323350131), we get a palindrome (68125655652186).
The spelling of 13105332302055 in words is "thirteen trillion, one hundred five billion, three hundred thirty-two million, three hundred two thousand, fifty-five".
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