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13105346614457 is a prime number
BaseRepresentation
bin1011111010110101001110…
…0001111001010010111001
31201101212012010202000201212
42332231103201321102321
53204204222213130312
643512302500052505
72521554464141216
oct276552341712271
951355163660655
1013105346614457
1141a2a45565429
121577aa2094135
13740aa1095946
143344331b2b0d
1517ad77e93822
hexbeb538794b9

13105346614457 has 2 divisors, whose sum is σ = 13105346614458. Its totient is φ = 13105346614456.

The previous prime is 13105346614421. The next prime is 13105346614471. The reversal of 13105346614457 is 75441664350131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13079065017001 + 26281597456 = 3616499^2 + 162116^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13105346614457 is a prime.

It is not a weakly prime, because it can be changed into another prime (13105346614417) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552673307228 + 6552673307229.

It is an arithmetic number, because the mean of its divisors is an integer number (6552673307229).

Almost surely, 213105346614457 is an apocalyptic number.

It is an amenable number.

13105346614457 is a deficient number, since it is larger than the sum of its proper divisors (1).

13105346614457 is an equidigital number, since it uses as much as digits as its factorization.

13105346614457 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3628800, while the sum is 50.

The spelling of 13105346614457 in words is "thirteen trillion, one hundred five billion, three hundred forty-six million, six hundred fourteen thousand, four hundred fifty-seven".