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13105403311411 is a prime number
BaseRepresentation
bin1011111010110101011011…
…1010001011010100110011
31201101212100002102112100001
42332231112322023110303
53204204331221431121
643512312243210431
72521556053100365
oct276552672132463
951355302375301
1013105403311411
1141a2a7456a714
121577ab9076a17
13740aaca57338
1433443a930d35
1517ad7ce42991
hexbeb56e8b533

13105403311411 has 2 divisors, whose sum is σ = 13105403311412. Its totient is φ = 13105403311410.

The previous prime is 13105403311321. The next prime is 13105403311423. The reversal of 13105403311411 is 11411330450131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13105403311411 - 221 = 13105401214259 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13105403311411.

It is not a weakly prime, because it can be changed into another prime (13105401311411) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552701655705 + 6552701655706.

It is an arithmetic number, because the mean of its divisors is an integer number (6552701655706).

Almost surely, 213105403311411 is an apocalyptic number.

13105403311411 is a deficient number, since it is larger than the sum of its proper divisors (1).

13105403311411 is an equidigital number, since it uses as much as digits as its factorization.

13105403311411 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2160, while the sum is 28.

Adding to 13105403311411 its reverse (11411330450131), we get a palindrome (24516733761542).

The spelling of 13105403311411 in words is "thirteen trillion, one hundred five billion, four hundred three million, three hundred eleven thousand, four hundred eleven".