Base | Representation |
---|---|
bin | 1011111010110101011011… |
… | …1010001011010100110011 |
3 | 1201101212100002102112100001 |
4 | 2332231112322023110303 |
5 | 3204204331221431121 |
6 | 43512312243210431 |
7 | 2521556053100365 |
oct | 276552672132463 |
9 | 51355302375301 |
10 | 13105403311411 |
11 | 41a2a7456a714 |
12 | 1577ab9076a17 |
13 | 740aaca57338 |
14 | 33443a930d35 |
15 | 17ad7ce42991 |
hex | beb56e8b533 |
13105403311411 has 2 divisors, whose sum is σ = 13105403311412. Its totient is φ = 13105403311410.
The previous prime is 13105403311321. The next prime is 13105403311423. The reversal of 13105403311411 is 11411330450131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13105403311411 - 221 = 13105401214259 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13105403311411.
It is not a weakly prime, because it can be changed into another prime (13105401311411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552701655705 + 6552701655706.
It is an arithmetic number, because the mean of its divisors is an integer number (6552701655706).
Almost surely, 213105403311411 is an apocalyptic number.
13105403311411 is a deficient number, since it is larger than the sum of its proper divisors (1).
13105403311411 is an equidigital number, since it uses as much as digits as its factorization.
13105403311411 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2160, while the sum is 28.
Adding to 13105403311411 its reverse (11411330450131), we get a palindrome (24516733761542).
The spelling of 13105403311411 in words is "thirteen trillion, one hundred five billion, four hundred three million, three hundred eleven thousand, four hundred eleven".
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