Base | Representation |
---|---|
bin | 1011111010110101011011… |
… | …1010101001011000110000 |
3 | 1201101212100002122210020112 |
4 | 2332231112322221120300 |
5 | 3204204331234401134 |
6 | 43512312250000452 |
7 | 2521556054122361 |
oct | 276552672513060 |
9 | 51355302583215 |
10 | 13105403434544 |
11 | 41a2a74644183 |
12 | 1577ab9116128 |
13 | 740aaca9b3b5 |
14 | 33443a963b68 |
15 | 17ad7ce691ce |
hex | beb56ea9630 |
13105403434544 has 60 divisors (see below), whose sum is σ = 26548608847992. Its totient is φ = 6266644032000.
The previous prime is 13105403434523. The next prime is 13105403434561. The reversal of 13105403434544 is 44543430450131.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 46589519 + ... + 46869969.
Almost surely, 213105403434544 is an apocalyptic number.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 13105403434544, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (13274304423996).
13105403434544 is an abundant number, since it is smaller than the sum of its proper divisors (13443205413448).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13105403434544 is a wasteful number, since it uses less digits than its factorization.
13105403434544 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 286026 (or 285997 counting only the distinct ones).
The product of its (nonzero) digits is 691200, while the sum is 41.
Adding to 13105403434544 its reverse (44543430450131), we get a palindrome (57648833884675).
The spelling of 13105403434544 in words is "thirteen trillion, one hundred five billion, four hundred three million, four hundred thirty-four thousand, five hundred forty-four".
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