13105403434561 has 2 divisors, whose sum is σ = 13105403434562. Its totient is φ = 13105403434560.

The previous prime is 13105403434523. The next prime is 13105403434589. The reversal of 13105403434561 is 16543430450131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7606233043600 + 5499170390961 = 2757940^2 + 2345031^2 .

It is a cyclic number.

It is not a de Polignac number, because 13105403434561 - 2³¹ = 13103255950913 is a prime.

It is not a weakly prime, because it can be changed into another prime (13105403434261) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552701717280 + 6552701717281.

It is an arithmetic number, because the mean of its divisors is an integer number (6552701717281).

Almost surely, 2^{13105403434561} is an apocalyptic number.

It is an amenable number.

13105403434561 is a deficient number, since it is larger than the sum of its proper divisors (1).

13105403434561 is an equidigital number, since it uses as much as digits as its factorization.

13105403434561 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 259200, while the sum is 40.

Adding to 13105403434561 its reverse (16543430450131), we get a palindrome (29648833884692).

The spelling of 13105403434561 in words is "thirteen trillion, one hundred five billion, four hundred three million, four hundred thirty-four thousand, five hundred sixty-one".