Base | Representation |
---|---|
bin | 1011111010110101011011… |
… | …1010101011100100101110 |
3 | 1201101212100002200020112022 |
4 | 2332231112322223210232 |
5 | 3204204331240143002 |
6 | 43512312250110142 |
7 | 2521556054160446 |
oct | 276552672534456 |
9 | 51355302606468 |
10 | 13105403443502 |
11 | 41a2a7464a987 |
12 | 1577ab911b352 |
13 | 740aacaa24b6 |
14 | 33443a967126 |
15 | 17ad7ce6bba2 |
hex | beb56eab92e |
13105403443502 has 4 divisors (see below), whose sum is σ = 19658105165256. Its totient is φ = 6552701721750.
The previous prime is 13105403443477. The next prime is 13105403443511. The reversal of 13105403443502 is 20534430450131.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3276350860874 + ... + 3276350860877.
It is an arithmetic number, because the mean of its divisors is an integer number (4914526291314).
Almost surely, 213105403443502 is an apocalyptic number.
13105403443502 is a deficient number, since it is larger than the sum of its proper divisors (6552701721754).
13105403443502 is an equidigital number, since it uses as much as digits as its factorization.
13105403443502 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6552701721753.
The product of its (nonzero) digits is 86400, while the sum is 35.
Adding to 13105403443502 its reverse (20534430450131), we get a palindrome (33639833893633).
The spelling of 13105403443502 in words is "thirteen trillion, one hundred five billion, four hundred three million, four hundred forty-three thousand, five hundred two".
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