13105405520131 has 4 divisors (see below), whose sum is σ = 13122057878632. Its totient is φ = 13088753161632.

The previous prime is 13105405520101. The next prime is 13105405520197. The reversal of 13105405520131 is 13102550450131.

13105405520131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13105405520131 - 2⁴¹ = 10906382264579 is a prime.

It is a super-2 number, since 2×13105405520131² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13105405520093 and 13105405520102.

It is not an unprimeable number, because it can be changed into a prime (13105405520101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8326178070 + ... + 8326179643.

It is an arithmetic number, because the mean of its divisors is an integer number (3280514469658).

Almost surely, 2^{13105405520131} is an apocalyptic number.

13105405520131 is a deficient number, since it is larger than the sum of its proper divisors (16652358501).

13105405520131 is an equidigital number, since it uses as much as digits as its factorization.

13105405520131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16652358500.

The product of its (nonzero) digits is 9000, while the sum is 31.

Adding to 13105405520131 its reverse (13102550450131), we get a palindrome (26207955970262).

The spelling of 13105405520131 in words is "thirteen trillion, one hundred five billion, four hundred five million, five hundred twenty thousand, one hundred thirty-one".