Base | Representation |
---|---|
bin | 1011111010110101011100… |
… | …0010100110100101000101 |
3 | 1201101212100020120202012221 |
4 | 2332231113002212211011 |
5 | 3204204332303121242 |
6 | 43512312402412341 |
7 | 2521556110630114 |
oct | 276552702464505 |
9 | 51355306522187 |
10 | 13105405520197 |
11 | 41a2a75839161 |
12 | 1577ab99610b1 |
13 | 740ab034b803 |
14 | 33443ad47c7b |
15 | 17ad7d22c167 |
hex | beb570a6945 |
13105405520197 has 2 divisors, whose sum is σ = 13105405520198. Its totient is φ = 13105405520196.
The previous prime is 13105405520101. The next prime is 13105405520237. The reversal of 13105405520197 is 79102550450131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12984246529956 + 121158990241 = 3603366^2 + 348079^2 .
It is a cyclic number.
It is not a de Polignac number, because 13105405520197 - 215 = 13105405487429 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13105405550197) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552702760098 + 6552702760099.
It is an arithmetic number, because the mean of its divisors is an integer number (6552702760099).
Almost surely, 213105405520197 is an apocalyptic number.
It is an amenable number.
13105405520197 is a deficient number, since it is larger than the sum of its proper divisors (1).
13105405520197 is an equidigital number, since it uses as much as digits as its factorization.
13105405520197 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 189000, while the sum is 43.
The spelling of 13105405520197 in words is "thirteen trillion, one hundred five billion, four hundred five million, five hundred twenty thousand, one hundred ninety-seven".
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