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13105405520132 = 223276351380033
BaseRepresentation
bin1011111010110101011100…
…0010100110100100000100
31201101212100020120202010112
42332231113002212210010
53204204332303121012
643512312402412152
72521556110626662
oct276552702464404
951355306522115
1013105405520132
1141a2a75839102
121577ab9961058
13740ab034b783
1433443ad47c32
1517ad7d22c122
hexbeb570a6904

13105405520132 has 6 divisors (see below), whose sum is σ = 22934459660238. Its totient is φ = 6552702760064.

The previous prime is 13105405520101. The next prime is 13105405520197. The reversal of 13105405520132 is 23102550450131.

It can be written as a sum of positive squares in only one way, i.e., 8154531316996 + 4950874203136 = 2855614^2 + 2225056^2 .

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1638175690013 + ... + 1638175690020.

It is an arithmetic number, because the mean of its divisors is an integer number (3822409943373).

Almost surely, 213105405520132 is an apocalyptic number.

It is an amenable number.

13105405520132 is a deficient number, since it is larger than the sum of its proper divisors (9829054140106).

13105405520132 is a wasteful number, since it uses less digits than its factorization.

13105405520132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3276351380037 (or 3276351380035 counting only the distinct ones).

The product of its (nonzero) digits is 18000, while the sum is 32.

Adding to 13105405520132 its reverse (23102550450131), we get a palindrome (36207955970263).

The spelling of 13105405520132 in words is "thirteen trillion, one hundred five billion, four hundred five million, five hundred twenty thousand, one hundred thirty-two".

Divisors: 1 2 4 3276351380033 6552702760066 13105405520132