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13105405520155 = 513676299477739
BaseRepresentation
bin1011111010110101011100…
…0010100110100100011011
31201101212100020120202011101
42332231113002212210123
53204204332303121110
643512312402412231
72521556110630024
oct276552702464433
951355306522141
1013105405520155
1141a2a75839123
121577ab9961077
13740ab034b7a0
1433443ad47c4b
1517ad7d22c13a
hexbeb570a691b

13105405520155 has 32 divisors (see below), whose sum is σ = 17191760544000. Its totient is φ = 9531859151232.

The previous prime is 13105405520101. The next prime is 13105405520197. The reversal of 13105405520155 is 55102550450131.

It is not a de Polignac number, because 13105405520155 - 27 = 13105405520027 is a prime.

It is a super-2 number, since 2×131054055201552 (a number of 27 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 27193276 + ... + 27671014.

It is an arithmetic number, because the mean of its divisors is an integer number (537242517000).

Almost surely, 213105405520155 is an apocalyptic number.

13105405520155 is a deficient number, since it is larger than the sum of its proper divisors (4086355023845).

13105405520155 is a wasteful number, since it uses less digits than its factorization.

13105405520155 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 484123.

The product of its (nonzero) digits is 75000, while the sum is 37.

Adding to 13105405520155 its reverse (55102550450131), we get a palindrome (68207955970286).

The spelling of 13105405520155 in words is "thirteen trillion, one hundred five billion, four hundred five million, five hundred twenty thousand, one hundred fifty-five".

Divisors: 1 5 13 65 67 335 871 4355 6299 31495 81887 409435 422033 477739 2110165 2388695 5486429 6210607 27432145 31053035 32008513 160042565 416110669 2080553345 3009277961 15046389805 39120613493 195603067465 201621623387 1008108116935 2621081104031 13105405520155