Base | Representation |
---|---|
bin | 1011111010110101011100… |
… | …0010100110100100011011 |
3 | 1201101212100020120202011101 |
4 | 2332231113002212210123 |
5 | 3204204332303121110 |
6 | 43512312402412231 |
7 | 2521556110630024 |
oct | 276552702464433 |
9 | 51355306522141 |
10 | 13105405520155 |
11 | 41a2a75839123 |
12 | 1577ab9961077 |
13 | 740ab034b7a0 |
14 | 33443ad47c4b |
15 | 17ad7d22c13a |
hex | beb570a691b |
13105405520155 has 32 divisors (see below), whose sum is σ = 17191760544000. Its totient is φ = 9531859151232.
The previous prime is 13105405520101. The next prime is 13105405520197. The reversal of 13105405520155 is 55102550450131.
It is not a de Polignac number, because 13105405520155 - 27 = 13105405520027 is a prime.
It is a super-2 number, since 2×131054055201552 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 27193276 + ... + 27671014.
It is an arithmetic number, because the mean of its divisors is an integer number (537242517000).
Almost surely, 213105405520155 is an apocalyptic number.
13105405520155 is a deficient number, since it is larger than the sum of its proper divisors (4086355023845).
13105405520155 is a wasteful number, since it uses less digits than its factorization.
13105405520155 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 484123.
The product of its (nonzero) digits is 75000, while the sum is 37.
Adding to 13105405520155 its reverse (55102550450131), we get a palindrome (68207955970286).
The spelling of 13105405520155 in words is "thirteen trillion, one hundred five billion, four hundred five million, five hundred twenty thousand, one hundred fifty-five".
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