Base | Representation |
---|---|
bin | 1011111010110101011100… |
… | …0010100110110110000011 |
3 | 1201101212100020120210201011 |
4 | 2332231113002212312003 |
5 | 3204204332303140113 |
6 | 43512312402421351 |
7 | 2521556110633225 |
oct | 276552702466603 |
9 | 51355306523634 |
10 | 13105405521283 |
11 | 41a2a75839a59 |
12 | 1577ab9961857 |
13 | 740ab034c15a |
14 | 33443ad48415 |
15 | 17ad7d22c63d |
hex | beb570a6d83 |
13105405521283 has 2 divisors, whose sum is σ = 13105405521284. Its totient is φ = 13105405521282.
The previous prime is 13105405521233. The next prime is 13105405521287. The reversal of 13105405521283 is 38212550450131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13105405521283 - 229 = 13104868650371 is a prime.
It is not a weakly prime, because it can be changed into another prime (13105405521287) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552702760641 + 6552702760642.
It is an arithmetic number, because the mean of its divisors is an integer number (6552702760642).
Almost surely, 213105405521283 is an apocalyptic number.
13105405521283 is a deficient number, since it is larger than the sum of its proper divisors (1).
13105405521283 is an equidigital number, since it uses as much as digits as its factorization.
13105405521283 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144000, while the sum is 40.
The spelling of 13105405521283 in words is "thirteen trillion, one hundred five billion, four hundred five million, five hundred twenty-one thousand, two hundred eighty-three".
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