Base | Representation |
---|---|
bin | 1011111010110101011101… |
… | …1011011001111011111011 |
3 | 1201101212100200211002000212 |
4 | 2332231113123121323323 |
5 | 3204204340434201021 |
6 | 43512313154021335 |
7 | 2521556220116621 |
oct | 276552733317373 |
9 | 51355320732025 |
10 | 13105412022011 |
11 | 41a2a7947a061 |
12 | 1577abbb7784b |
13 | 740ab17b703a |
14 | 33443bb5b511 |
15 | 17ad7dab385b |
hex | beb576d9efb |
13105412022011 has 2 divisors, whose sum is σ = 13105412022012. Its totient is φ = 13105412022010.
The previous prime is 13105412022007. The next prime is 13105412022071. The reversal of 13105412022011 is 11022021450131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13105412022011 - 22 = 13105412022007 is a prime.
It is not a weakly prime, because it can be changed into another prime (13105412022071) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552706011005 + 6552706011006.
It is an arithmetic number, because the mean of its divisors is an integer number (6552706011006).
Almost surely, 213105412022011 is an apocalyptic number.
13105412022011 is a deficient number, since it is larger than the sum of its proper divisors (1).
13105412022011 is an equidigital number, since it uses as much as digits as its factorization.
13105412022011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 480, while the sum is 23.
Adding to 13105412022011 its reverse (11022021450131), we get a palindrome (24127433472142).
The spelling of 13105412022011 in words is "thirteen trillion, one hundred five billion, four hundred twelve million, twenty-two thousand, eleven".
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