Base | Representation |
---|---|
bin | 1011111010110101100011… |
… | …0001001010101101100010 |
3 | 1201101212102021010021120101 |
4 | 2332231120301022231202 |
5 | 3204204412213112114 |
6 | 43512315315533014 |
7 | 2521556612164105 |
oct | 276553061125542 |
9 | 51355367107511 |
10 | 13105434504034 |
11 | 41a2a90135144 |
12 | 1577b075ba16a |
13 | 740ab6359102 |
14 | 334440b3073c |
15 | 17ad80a54d74 |
hex | beb58c4ab62 |
13105434504034 has 16 divisors (see below), whose sum is σ = 20814790602528. Its totient is φ = 6167181228352.
The previous prime is 13105434504007. The next prime is 13105434504061. The reversal of 13105434504034 is 43040543450131.
It is an interprime number because it is at equal distance from previous prime (13105434504007) and next prime (13105434504061).
It is a junction number, because it is equal to n+sod(n) for n = 13105434503984 and 13105434504002.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 67149 + ... + 5120095.
It is an arithmetic number, because the mean of its divisors is an integer number (1300924412658).
Almost surely, 213105434504034 is an apocalyptic number.
13105434504034 is a deficient number, since it is larger than the sum of its proper divisors (7709356098494).
13105434504034 is a wasteful number, since it uses less digits than its factorization.
13105434504034 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5129249.
The product of its (nonzero) digits is 172800, while the sum is 37.
Adding to 13105434504034 its reverse (43040543450131), we get a palindrome (56145977954165).
The spelling of 13105434504034 in words is "thirteen trillion, one hundred five billion, four hundred thirty-four million, five hundred four thousand, thirty-four".
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